abaqus利用Python实现部件合并：在Abaqus Python中用Element()构造函数创建部件元素

我不能用Abaqus中Part对象的Element()构造函数创建元素。Node()构造函数没有问题，但是当您尝试使用以前生成的节点创建元素时，它会向您显示以下错误警告：

在运行脚本之前，部件网格在Abaqus CAE树(part Recuadro)中显示为空，运行脚本后不再为空，因此我知道网格已经生成。在

这是我的剧本：import sys

import mesh

import part

from abaqus import *

from odbAccess import *

from abaqusConstants import *

from caeModules import *

from driverUtils import executeOnCaeStartup

#

# Función que da el número del nodo en función de las fila y columna de elementos

#

def nnodo(i,j,ne):

n = (2*ne+1)*(i-1)+j

return n

filecae= 'E:\ESI\Fatiga\Cotacto Cilindrico\ABQ\CC-Crack-0.cae'

openMdb(filecae)

# Coordenadas del arranque de la grieta en "Recuadro"

x0 =0.0

y0 = -0.002

z0 = 0.0

delta=[0]

# Dimensiones del recuadro x € [x0-a,x0+a] y € [y0-b, y0]

a=0.2

b=0.2

# Tamaño deseado de los elementos ~ le x le

le = 0.05

# Tamaño inicial de los elementos ~ dx x dy

Nex = 2*int(a/le)

Ney = int(b/le)

Nnx = 2*Nex+1

Nny = 2*Ney+1

dx = 2*a/Nex

dy = b/Ney

Nnodos = Nnx*Nny

Nelems = Nex*Ney

inod = range(Nnodos-1)

ielm = range(Nelems-1)

for i in range(Nny):

delta.append(0)

# Coordenadas de los nodos de la malla inicial

recuadro=mdb.models['P22'].parts['Recuadro']

recuadro1=mdb.models['P22'].rootAssembly.instances['Recuadro-1']

recuadro.generateMesh(regions=(recuadro.faces[0],))

for i in range(1,Nny+1):

dx1 = (Nex*dx/2 - delta[i])/Nex

dx2 = (Nex*dx/2 + delta[i])/Nex

y = y0 - (i-1)*dy/2

for j in range(1,Nnx+1):

if float(i)/2. <> int(float(i)/2. ) or float(j)/2. <>int(float(j)/2. ):

k = (2*Nex+1)*(i-1)+j

if j<=Nex+1:

x = x0 - Nex*dx/2 + (j-1)*dx1

else:

x = x0 - delta[i] + (j-Nex-1)*dx2

recuadro.Node(label = k, coordinates=(x, y, 0.))

# Conectividades de los elementos de la malla inicial

for i in range(1,Ney+1):

for j in range(1,Nex+1):

k = Nex*(i-1)+j

n1 = recuadro.nodes[nnodo(2*i+1, 2*j-1, Nex)]

n2 = recuadro.nodes[nnodo(2*i+1, 2*j , Nex)]

n3 = recuadro.nodes[nnodo(2*i+1, 2*j+1, Nex)]

n4 = recuadro.nodes[nnodo(2*i , 2*j+1, Nex)]

n5 = recuadro.nodes[nnodo(2*i-1, 2*j+1, Nex)]

n6 = recuadro.nodes[nnodo(2*i-1, 2*j , Nex)]

n7 = recuadro.nodes[nnodo(2*i-1, 2*j-1, Nex)]

n8 = recuadro.nodes[nnodo(2*i , 2*j-1, Nex)]

recuadro.Element(label = k, elemShape= QUAD8, nodes=(n1, n2, n3, n4, n5, n6, n7, n8))

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